222 392318660. minutes. Solving this pulveriser, we get x = 4081170, y = Hence the ahargana-4081170 days, and the corresponding mean longitude of Venus = 10 signs 24° 20' 10". Again EXAMPLES revolution-number of Saturn reduced to minutes civil days in a yuga Multiplying 17 by 5259725 and dividing the product by 60, the quotient is 1490255: this is the residue of the minutes. The resulting pulveriser is = 10552608 x 1490255 5259725 where x denotes the ahargana and y the mean longitude of Saturn in minutes. Solving this pulveriser, we get x = 3308510, y = 6637877. 3308510, and the mean longitude of Hence the required ahargana Saturn 3 signs 21° 17' 17". y, = 10552608 5259725 19. The sum of the (mean) longitudes of Mars and the Moon is calculated to be 5 signs, 7 degrees, and 9 minutes. O you, well versed in the (Arya) bhata-tantra, quickly say the ahargana and also the (mean) longitudes of the Moon and Mars.¹ 11. The following is the solution of this example: Mean longitude of Mars + mean longitude of the Moon Also sum of the revolution-numbers of Mars and the Moon civil days in a yuga y, 5 signs 7° 9' = 9429'. Multiplying 9429 by 26298625 and dividing the product by 21600, the quotient is 11480080: this is the residue of the revolutions. We have therefore to solve the pulveriser 1000836 x 11480080 26298625 1000836 26298625 where x is the required ahargana. Solving the pulveriser, we get x = 5646655. From this ahargana we can easily calculate the mean longitudes of Mars and the Moon. ¹ For Govinda Svāmi's modification of this example, see supra, chapter I, under stanza 52.
