EXAMPLES By the usual method, we get x = 74350409 and y 845180. = 17. The signs, degrees, and minutes of the (mean) longi- tude of Jupiter have been destroyed by a mischievous child; nine seconds are seen to remain (undisturbed). Say therefrom the ahargana and the mean longitude of Jupiter. The following is the solution of this example: Revolution-number of Jupiter reduced to minutes civil days in a yuga - 26224128x788958 5259725 26224128 5259725 221 Multiplying 9 by 5259725 and dividing the product by 60, we obtain 788958 as the quotient. This is the residue of the minutes. Then we have to solve the pulveriser where x denotes the ahargana and y the longitude of Jupiter in terms of minutes. Solving the pulveriser, we get x = 2269811, y = 11316906', i. e., 523 revs., 11 signs, 5 degrees, 6 minutes. The required ahargana is there- fore 2269811 days, and the mean longitude of Jupiter is 11 signs 5° 6′ 9″.. 18. The revolutions, etc., up to the minutes of the (mean) longitude of Venus are destroyed; 10 seconds are seen to re- main intact. Of Saturn, 17 seconds are found to remain in- tact. Quickly say (the mean longitudes of) them and also the ahargana (in the two cases). The following is the solution of this example: Revolution-number of Venus reduced to minutes civil days in a yuga 505611936 5259725 Multiplying 10 by 5259725 and dividing the product by 60, the quotient is 876620: this is the residue of the minutes. The resulting pulveriser is 505611936 x - 876620 5259725 where x is the ahargana and y the corresponding 18ngitude of Venus in
