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108 THEORY OF THE PULVERISER Mutually dividing 36641 and 39479375 until the remainder is 1 (i.८., monzero), and writing down the successive quotients one below the other, we get 10766 15 Writing down the mats The reduced dividend and reduced divisor are 1 and 3 respectively. Since the number of quotients obtained is even, and the interpolator is nega tive, we follow the rule for the negative interpolator and thus obtain 27 for the mat. Multiplying 1 by 27 and subtracting 2+ from the product, we get 3 which divided by the reduced divisor 3 yields I as the quotient. 22 and this quotient under 1076 15 22 27 the chain of quotients, Reducing the chain, we successively obtain 10766 1076 10766 10766 10766 310804439 (multiplier) 15 15 15 15 28689 288689 (uotient) 2 18665 18665 7 8714 8714 22 1237 1237 55 55 27 Dividing 310804 39 by 39479375, and 288689 by 36641, we get 346688814 and 32202 respectively as remainders. Therefore =346688814,5y=32202. These are the least integral values satisfying the equation. कृत्वा वा कर्तव्यः कुट्टाकारस्तु रूपयुतिवियुती । गुणकारो लब्धं च स्यातां तदुपर्यधःशेषौ ॥ १२ ॥