44 where x denotes the required ahargana. PLANETARY PULVERISER The minimum solution of this equation is x= 10157490, y = 386459. The required ahargana is, therefore, 10157490. The mean longitudes of the Moon and Mars can be easily calculated from this ahargana. Example 2. "The difference between the mean longitudes of Mars and Jupiter is exactly 5 signs. Say what is the number of days elapsed since the beginning of Kaliyuga and what are the (mean ) longitudes of Jupiter and Mars." 1 The revolution-number of Mars The revolution-number of Jupiter Their difference Also the number of civil days 2296824. 364224. 1932600. =1577917500. The H. C. F. of 1932600 and 1577917500 is 300. Therefore, the abraded difference of the revolution-numbers of Mars and Jupiter 1932600 300, i.e., 6442, and the abraded number of civil days = 1577917500 300, i.e., 5259725. The difference between the mean longitudes of Mars and Jupiter = 5 signs. Therefore, by stanza 46(ii), the residue of revolutions=2191552. Hence we have to solve the equation 6442 x 2191552 5259725 where x denotes the required ahargana. 1 Mbh, viii. 20. =y, The minimum solution of this equation is X= 1133606, y = 1388. The required ahargana is therefore 1133606. The corresponding mean longitudes of Mars and Jupiter may be easily obtained.
