42 PLANETARY PULVERISER Here, according to Bhaskara I's interpretation, the part of the re- volution to be traversed by the Sun = 7 signs 100'. The corresponding residue of revolutions = 123707. This is positive. We have, therefore, to solve the equation 576 x 123701 210389 where x is the required ahargana, and y-1 the number of years elapsed. Mutually dividing 576 and 210389 and taking 1 for the optional number (mati) after six quotients, we get the following chain which reduces to 365 3 1 6 2 4 1 (mati) 61851 1310408037 3587617 Dividing 1310408037 by 210389 and 3587617 by 576, we obtain as remainders 105345 and 289 respectively. Therefore x = 105345, y = 289. Hence the required ahargana 105345, and the number of years elapsed 288. Note. According to Govinda Svāmi's interpretation the part of the revolution to be traversed by the Sun = 4 signs 1° 40'. The corresponding residue of the revolution = 71104. The resulting pulveriser is 576x+71104 210389 of which the solution is x = 186889, y = = y, = 512. Therefore, the required ahargaṇa 186889, and the number of years clapsed = 511,
