40 PLANETARY PULVERISER 7003, y == 4, giving x 1751. Solving equation (4), we get X = Hence the required ahargana is 1750, and the number of revolutions performed by the Sun is 4. Example 2. "The revolutions, etc., of the Sun's mean longitude, calculated from an ahargana plus a few nädis elapsed, have now been destroyed by the wind; 71 minutes are seen by me to remain intact. Say the ahargana, the Sun's (mean) longitude, and the correct value of the nadis (used in the calculation)." 1 Here we have to solve the equation 576x12x30×60(x+n/60) - -71 210389 = y, (5) where x is the ahargana, y the minutes traversed by the Sun since the beginning of the Kaliyuga, and n the nädis elapsed. As this equation is of the form (1), we reduce it to the form (2), and thus we get where X 60x+n. 207360X-71 210389 = y, Solving equation (6), we obtain 43203, y = 42581, whence we have x = 720, and n = 3. (6) the mean Hence the ahargana is 720, the nādis elapsed are 3, and longitude of the Sun is 42581 minutes, i.e., 11 signs, 19 degrees, and 41 minutes. A rule for getting the other solutions of a pulveriser with the help of the known minimum solution : 50. (To obtain the other solutions of the pulveriser) the intelligent (astronomer) should again and again add the divisor to the multiplier and the dividend to the quotient as in the process of prastara ("representation of combinations"). 1 Bhaskara I's example, occurring in his comm, and in MBh, viii. 23. on A, iii. 32-33,
