34: Hence the above rule. Example. "The mean (position) of the Sun has been observed by me at sunrise to be in the sign Leo in the middle of the navamāṁsa Sagittarius. Calculate the ahargana according to the (Arya)bhaṭa-sastra, and also the revolutions performed by the Sun since the beginning of Kaliyuga."1 The mean longitude of the Sun PLANETARY PULVERISER The abraded revolution-number of the Sun = 576, and the abraded number of civil days in a yuga = 210389. Hence, by the above rule, the residue of revolutions = 86688. We have, therefore, to solve the equation 4 signs 28° 20' = 8900'. 576 x 86688 210389 where x is the ahargapa and y the number of revolutions performed by the Sun. Solving this equation with unit residue, we get 94602. where d 0, 1, 2, 3, =y, y = 259. Deducing the solution for the given residue, we get x = 105345, y = 288, ... which is the minimum solution of the problem. The general solution is X = 210389+105345, y 576α + 288, A rule for solving a pulveriser when the dividend is greater than the divisor: 47. When the dividend is greater than the divisor, then, having subtracted the greatest multiple of the divisor (from ¹ Bhaskara I's example occurring in his comm. on Ā, ii. 32-33, 2 See the rule given in stanzas 45-46(i).
