. PLANETARY PULVERISER Reducing the chain, we successively get 10766 10766 10766 10766 10766 3108044439 (multiplier) 15 15 15 15 288689 288689 (quotient) 2 18665 18665 32 2 7 22 55 27 2 7 8714 8714 1237 1237 55 Dividing 3108044439 by 394479375, and 288689 by 36641, we obtain 346688814 and 32202 respectively as remainders.¹ These are the minimum values of x and y satisfying the above equation. Therefore, the required ahargana 346688814, and the revolutions performed by Saturn 32202. = General solution. The general solution of the above equation (vide stanza 50) is x=394479375d +346688814, y == 3664132202, where = 0, 1, 2, 3, An alternative rule: 45-46(i). Alternatively, the pulveriser is solved by subtrac- ting one (i.e., by assuming the residue to be unity). The upper and lower quantities (in the reduced chain) are the (correspon- ding) multiplier and quotient (respectively). By the multiplier and quotient (thus obtained) multiply the given residue, and then divide the respective products by the abraded divisor and dividend. The remainders obtained are here (in astronomy) the ahargana and the revolutions (performed respectively). This division is performed only when the multiplier and quotient are greater than the divisor and dividend respectively.
